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## Analytical Reasoning Set 2

 120 students are arranged by two teachers Baman and Chaman, in 'x' rows and 'y' columns such that each row has the same number of students. Similarly, every column has same number of students. Each of the students hs 15 pencils initially. Every student gets extra pencils from Baman. If he is in the mth row, he gets 'm' pencils. Thereafter, each of the students gives away some pencils to Chaman. If the student is in the nth column, he gives away 'n' pencils. Finally, the total number with the students is 16 times the total number of students.

## Questions Set 2

Q1) What is the value of 'x'?
1) 10
2) 12
3) 15
4) 20

Q2) How many pencils did students give away to Chaman?

1) 640
2) 660
3) 680
4) Cannot be Determined

Q3) How many pencils were given to the students by Baman?

1) 540
2) 660
3) 780
4) Cannot be Determined

SOLUTIONS:

Initially students had a total of 15xy pencils with them, where xy = 120.
Let the total number of pencils given to the students by Baman be 'J' and the total number of pencils given by the students to Chaman be 'M'.
J = (y + 2y +....+ xy), M = (x + 2x +...+ yx)
J = y(1 + 2 +...+ x), M = x(1 + 2 +...+ y)
15xy + J - M = 16xy where xy = 120.
J - M = xy = 120 i.e. x - y = 20
Therefore, x = 12, y = 10.
Pencils given to Chaman = M = 12(1 + 2 +...+ 10) = 660
Pencils given to the students by Baman = J = 120 + M = 780

Logical Reasoning