Calendar


@ : Home > Quantitative Aptitude > Calendar > Practice Questions

Practice Questions - Calendar

Q9) Which of the following is a leap year?
1) 600
2) 2100
3) 1700
4) 800

Solution: Century year is a leap year if it is divisible by 400.
Hence, option 4.

Q10) If 11th Nov, 2012 is a Sunday. What day of the week will it on 15th Nov, 2014?
1) Thursday
2) Friday
3) Saturday
4) Monday

Solution: Odd days from 11th Nov, 2012 to 11th Nov, 2014 = 2
Odd days from 11th Nov, 2012 to 15th Nov, 2014 = 6
So, required day is 6 days after Sunday.
Hence, option 3.

Q11) How many days are there in 2y weeks and 3y days.
1) 17y
2) 5y
3) 14y
4) None of these

Solution: Days in 2y weeks and 3y days = 14y + 3y = 17y days
Hence, option 1.


Q12) What day of the week was on March 13, 1925?
1) Sunday
2) Saturday
3) Thursday
4) Friday

Solution: Odd years in 400 years are '0'. Therefore, odd days in 1600 years are '0'.
From 1601 - 1900 (300 years) odd days = 1.
From 1901 - 1924 (24 years). There are 6 leap years from 1901 - 1924, 18 normal years from 1901 - 1924.
Odd days from 1901 - 1924 is ( 6 × 2 + 18 × 1 ) = 30 odd days = 2 odd days.
From January 1925 - March 13, 1925
Odd days = 3(January) + 0(February) + 6(Till March 13) = 9
Total Odd days till March 13, 1925 = 12 odd days = 5 odd days. Therefore, March 13, 1925 is Friday.
Hence, option 4.

Q13) What day of the week was on July 17, 1776?
1) Wednesday
2) Saturday
3) Friday
4) Monday

Solution: Counting odd days
In 1600 yr = 0
In 100 yr = 5
In 75 yr = 18 leap years + 57 ordinary years = (18 × 2 + 57 × 1) = 93 odd days = 13 weeks + 2 days = 2 odd days.
Period upto July 17, 1776 = Period from 1st January 1776 to 17th July 1776 = January + February + March + April + May + June + July = 3 + 1 + 3 + 2 + 3 + 2 + 3 = 3 odd days.
Total number of odd days = 5 + 2 + 3 = 3 odd days.
Therefore, July 17, 1776 is Wednesday.
Hence, option 1.



Follow us on: Facebook


Aptitude Main Menu

Aptitude Practice Tests